Important questions about Advanced Surveying. Advanced Surveying MCQ questions with answers. Advanced Surveying exam questions and answers for students and interviews.

1. Spring tides are caused when

Options

A : sun and moon are in line with earth

B : solar tidal force acts opposite to lunar tidal force

C : solar tidal force and lunar tidal force both coincide

D : none of these.

2. By applying clockwise swing to right projector, maximum y -parallax is introduced in the model at

Options

A : position 1

B : position 2

C : position 4

D : position 6.

4. The foot of the perpendicular on the picture plane through the optical centre of the camera lens, is known as

Options

A : isocentre

B : principal point

C : perspective centre

D : plumb line.

6. The net ground area of a vertical photograph 20 cm x 20 cm on scale 1 : 10,000 having overlaps 60% and 30%, is

Options

A : 0.50 sq km

B : 0.56 sq km

C : 0.60 sq km

D : 0.64 sq km.

7. The rate of change of parallax dp / dh with respect to change in h , may be expressed as

Options

A : fB /( H - h )

B : fB /( H - h ) 2

C : fB /( H + h )

D : fB /( H + h ) 2 .

8. Pick up the in-correct statement from the folowing :

Options

A : Correction for refraction is always negative

B : Correction for parallax is always positive

C : Correction for semi-diameter is always negative

D : Correction for dip is always negative

9. The prime vertical passes through

Options

A : the east point of the horizon

B : the west point of the horizon

C : the zenith point of the observer

D : the nadir point of horizon

10. The difference of parallax for a given difference in elevation is independent of

Options

A : focal length of the camera

B : overall size of the photo graphs

C : percentage of overlap

D : all the above.

1. The point on the photograph where bisector between the vertical line through optical centre of the camera lens and the plate perpendicular meets, is known as

Options

A : principal point

B : isocentre

C : plumb point

D : perspective centre.

2. The negative sign is assigned to

Options

A : reduction to mean sea level

B : correction for horizontal alignment

C : correction for slope

D : correction for slope

3. The method of surveying by triangula-tion was first introduced by the Dutchman Snell in

Options

A : 1600

B : 1615

C : 1630

D : 1650

4. The angular distance of a heavenly body from the equator, measured along its meridian, is called

Options

A : declination

B : altitude

C : zenith distance

D : co-latitude.

5. Triangulation surveys are carried out for providing

Options

A : planimetric control

B : height control

C : both planimetric and height control

D : none of these.

6. The latitude of a place was obtained by subtracting the declination of a star from its zenith distance, the observed star was between

Options

A : horizon and equator

B : zenith and pole

C : equator and zenith

D : pole and horizon.

7. When a star is between the pole and the horizon, the relationship between latitude (?), zenith distance ( z ) and declination ?, is

Options

A : ? = z + ?

B : ? = ? - z

C : ? = 180° - ( z + ?)

D : ? = ( z + ?) - 180°.

8. The station pointer is generally used in

Options

A : Triangulation surveying

B : Astronomical surveying

C : Hydrographical surveying

D : Photogrammetric surveying.

10. If S is the sum of three angles of a spherical triangle, the spherical excess equals

Options

A : S - 90°

B : S - 180°

C : S - 270°

D : S - 360°.

1. The true and mean suns occupy the same meridian at the same time on

Options

A : April 15

B : June 14

C : September 1

D : December 25

2. With standard meridian as 82° 30' E the standard time at longitude 90° E is 8 h 30 m. The local mean time at the place will be

Options

A : 7 h 00 m

B : 7 h 30 m

C : 8 h 00 m

D : 8 h 30 m

3. The normal longitudinal overlap is generally kept